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Competing over a forcing notrump

West
J632
64
Q93
Q1053
North
Q108
J972
J864
J8
East
K54
A10
K1075
AK97
South
A97
KQ853
A2
642
W
N
E
S
1
P
1NT
X
P
2
P
P
P
D
2 West
NS: 0 EW: 0

Matchpoints at the club, 2 led, result 2 -100. A bidding poll had the majority doubling, with a substantial number passing: https://bridgewinners.com/article/view/bidding-problem-2-knvsp8mq3p/ . I was curious what effect the forcing notrump should have here: East does not have four spades, and will get another chance to bid. But East does have 17 hcp, short hearts and support for the other suits. I'll include a quick poll but I'm mostly interested in discussion of this situation. Of course, Bergen fanatics will be playing 3 as South on this hand. Double Dummy has both 2 and 3 making, 3 down 1, but I think the 4-4 club fit would've been easier to play and, in general, safer.

The given auction and result are fine
The auction is fine, West should make 2.
East should pass 1NT, double North's correction to 2.
West should respond 2 to East's immediate double, planning to compete in spades later.
Other.

Sorry, to answer polls. Registered users can vote in polls, and can also browse other users' public votes! and participate in the discussion.

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