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Opening lead out of turn.

Pairs.  MP.   Contract 4 South

West
KQJ765
84
Q9
964
North
43
AKJ32
K86
875
East
A
97
J10754
KJ1032
South
10982
Q1065
A32
AQ
D

East leads A out of turn.   South calls TD.   After hearing all the 5 options,  South decides that it can be good for him to have tha A as pentalty card,  so he offers west to lead any card he wants.

West leads 6 and the South makes 10 tricks.  South calls TD and is not happy.  With the normal K lead he would have made 11 tricks.

What should TD do?

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Thank you all for your comments about this case. Here is my option.

The facts are...

  1. The existence of A is UI for West, and AI for declarer. Law 16D and 50E.
  2. South's reasoning for giving a free lead to west is not known, but was not stupid, but I think a little against odds. That does not at all have any influences about the ruling.
  3. West was probably always going to lead spade, but 99% K.
  4. The fact that South did not find his way for throw in for diamonds was not serious error (Law 12C1b), although it was unrelated to the infraction.

My ruling is based on law 50E3 and law 12C.

The lead out of turn, gave E/W 3 tricks, If it had not happened, it is likely that declarer would get 11 tricks. I rule 11 tricks for both sides

Weighted score is also an optinon. e.g. 75% 11 tricks, 25% 10 tricks.

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30/8/2013   Well I do not know what I was writing here abouve.  Weighted score is not an option.  Always 11 tricks.

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