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All comments by Andrzej Matuszewski
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Exactly!! So E has 3 spades (at the beginning).
an hour ago
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Next tip: W for typical take-out double “must” have 4 spades. Already showed 5 clubs. Count given by E in the first trick gives him 4 diamonds. So he heas void in hearts!
2 hours ago
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If analyze carefully Craig we can not drop honor…
10 hours ago
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I do not know if this is a hint or it makes problem more difficult:
They had a chance to set us but they did not notice this non-trivial chance…
11 hours ago
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Exactly (when talking about type of scoring)! We have a chance to win.
11 hours ago
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What was the lead?
Nov. 17
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First of all: You have to consider seriously winning A in the second trick.
Nov. 17
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2 has 2 shortcomings:
1. They can double us.
2. If they will play something from S's side, pd's spades lead can be bad.
Nevertheless at MPs, when we need a swing 2, must be considered very seriously. Especially because their most probable contract will be 3 and then I'll be the first leader with quite safe diamonds lead and with their high spades that most probably will be seen in dummy.
Nov. 16
Andrzej Matuszewski edited this comment Nov. 16
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2 is bad IMHO. It says either: “I have 5 spades” or “I have minimum”. Both are false.
Nov. 14
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Yes I really appreciated very nice solution. Also N's mistake was far from obvious. My intentions were sincere and positive but could be treated as critisism. Sorry for that!
Nov. 14
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Sorry! The point is elsewhere.
You are right. I must cover 8.
The ending is following with 2 tricks already taken by NS.
___________J98
___________-
___________9
___________K
-_____________________K105
-_____________________-
7_____________________-
J764__________________A9
___________Q7
___________-
___________3
___________Q10

You can not take 3 tricks. Also you couldn't take 4 tricks in 6-card ending.
Nov. 14
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I considered an artificial and specific situation, where N has singleton K, because this is the only possibility to (rationally) drop the king. If you want I'll make an analysis of this situation.
Nov. 14
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I tried to “repair” distribution to make this new coup definitely optimal, but it seems impossible. Even if we make N's K singleton, they (NS) have a fine defense:
After: S played 8 covered by W's ten, N must duck!!!
Nov. 14
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No, Steve. This diamond is necessary to make the squeeze against N, it seems.
Nov. 14
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Sorry, I did not notice. N made error dropping 2 clubs.
Nov. 14
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What 3 would mean in your methods Rafael?
Nov. 14
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You wrote that the defense was not optimal. May be this is a point. It seems difficult to predict the actual position after N dropped K.
Nov. 14
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200% pass at IMPs, but 20% at MPs.
Nov. 12
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How my pd will understand my 3?
Nov. 11
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Let mi say my general opinion.
Changing by South to K looks like something nearly idiotic, taking into account that declarer must have A.
In fact - at average+ level - it is very meaningful alternative. From the bidding it was very probable that declarer has 5 diamonds. In this case K in the second trick is very reasonable taking into account error of N in the first trick.
Nov. 11
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