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Bridge sometimes is very strange! I did not tell nor ask you what are you going to put for a second spade from dummy. Yes you are in a sort of squeeze in the second trick. It seems that a good solution is to dump a CLUB. East correctly assumed that you have 4 hearts. In such case a DIAMOND SHIFT makes problems. If we have to finesse in hearts we MUST WIN THE ACE. If we assume Lefty has the heart queen (which probably gives 3 clubs in hands if E) we must play ♥J in the fourth trick!!!

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My hint is the following: How it is possible that W in unfavorables bids? Probability that he has void in hearts is close to 50%. And it is not easy to play hearts at 0-4 division…

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Thanks Brad and Gregory for discussion in a very difficult topic!!! My “solution” is the following. Pd has at most: 2 hearts, 2 spades and 3 clubs. So he has at least 6 diamonds. So I must pass!!! Additionally i have very good first lead: ♦A!!!

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Serge is right in sense that large part of field automatically bids 1N. The latter contract seems to be easier for the hand and gives better score if we take 7 or 8 tricks for both contracts. This is why our situation is difficult.

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The only advantage (I see) of this line is a possibility that E will enter with ♣A. This possibility is extremely low probable when it was nearly established that declarer has 3 diamonds. From this point of view Michal Czerwonko proposal is better founded, since declarer can have 4+ diamonds in the second trick.

Andrzej Matuszewski

I did not tell nor ask you what are you going to put for a second spade from dummy.

Yes you are in a sort of squeeze in the second trick.

It seems that a good solution is to dump a CLUB.

East correctly assumed that you have 4 hearts. In such case a DIAMOND SHIFT makes problems.

If we have to finesse in hearts we MUST WIN THE ACE. If we assume Lefty has the heart queen (which probably gives 3 clubs in hands if E) we must play ♥J in the fourth trick!!!

Andrzej Matuszewski

Andrzej Matuszewski

Andrzej Matuszewski

Andrzej Matuszewski

Andrzej Matuszewski

My “solution” is the following.

Pd has at most: 2 hearts, 2 spades and 3 clubs. So he has at least 6 diamonds.

So I must pass!!! Additionally i have very good first lead: ♦A!!!

Andrzej Matuszewski

Andrzej Matuszewski

How can I reason from there?

Andrzej Matuszewski

Andrzej Matuszewski

This is why our situation is difficult.

Andrzej Matuszewski

Andrzej Matuszewski

Andrzej Matuszewski

Andrzej Matuszewski

Andrzej Matuszewski

Andrzej Matuszewski

Andrzej Matuszewski

Andrzej Matuszewski

Andrzej Matuszewski

Andrzej Matuszewski