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I'd say that N could pass but it is not very easy.
Jan. 14
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OK, I give the answer. May be there is: something illogical or a simple error.
The Chance is the following:
1. E has AQ2
2. After winning spades trick and cashing K. He will not play x.
If I play 6 in the third trick I get the following Chance.
Say E plays Q.
I win with the high spade and play something in spades different from 3.
E wins and then I enter dummy with 4 to cash a good J. I can not enter in diamonds because E will trup the trick.

To play for this Chance I can not play 3 in the third trick.
Jan. 14
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No, it is standard carding here. Most propbably it is singleton or doubleton.
Jan. 14
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Say, you played 3. 5, J, Q followed. In original problem, E played K and then x. This must happen when you see the closed hand.
But from E's point of view, the second continuation is not absolutely obvious. He may continue clubs. Or play Q.
Jan. 14
Andrzej Matuszewski edited this comment Jan. 14
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I give you something that I treat as a hint.
Assume there are 5 hearts and only 3 diamonds in dummy. Say, 3 becomes 3.
Jan. 13
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In what sense, Steve?
Jan. 13
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I think that real expert feels the LAW. The only problem is what number of artificial sequences (connected with the LAW) he is going to include in the bidding system? But this is quite difficult to assess since he normally plays with different partners.
Jan. 6
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The only declarer's distribution that can be considered is:
3=3=3=4. With this distribution, however, he would play differently.
Jan. 3
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A heart from the closed hand. If he had only 2 spades, then 2 hearts, but in this case we can easly set him NOT PLAYING SPADES.
Jan. 3
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Sometimes we start King from AK. The key of this problem was a false hint in spades. In practice many W's would play for that.
Jan. 2
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Yes, your reasoning is absolutely VALID! Also pd has to drop all - other then ace - clubs. In consequence he will keep 3 diamonds.
Dec. 21, 2019
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I agree that NS players with some imagination will keep only singletons in clubs. Little more imagination is necessary to infere that spades drops from N means exactly singleton or doubleton if he does not hold the queen.
So clubs lead does not give much information. Nevertheless it is possible to make error in case Q is in dummy.
Dec. 21, 2019
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Good point Ken! Here, however, I'm not sure if I can rely on unknown pd's sequence of spots (suit preference is only an alternative). After clubs lead eveything is clear.
Of course it does not mean that I try to prove that something is optimal.
Dec. 20, 2019
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Take 2 possibilities:
1. E has everything in hearts.
2. You “kill” pd's figure.
Then declarer plays his hearts. You and pd keep clubs. What will the ending be?
Ian, I'm not teaching here. Yes I have some mathematical models for declarer's play/defense, but forums are not good platforms for presentation.
I try to provoke with some unusual hands.
Dec. 20, 2019
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E had Kx in spades, 8 hearts, AQx in diamonds and void in clubs. Small club was the best lead. But I do not insist on that.
I repeat: In many positions one can not prove that there exists an optimal solution. The discussion has its own value.
Dec. 19, 2019
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It is quite possible that form of my articles is controvercial or even very irritating. Nevertheless I try to present my vision of bridge. Very often the optimal solution can not be find, so the only possible method is through the expert discussion.
Person who enters here for the first as possibly the last time can not assess if someone is expert. I expect your support…
Dec. 19, 2019
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Not elegant statement Adam! Why did you put it here and not in my earlier articles?
Dec. 19, 2019
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7 hearts and 5 clubs - is it real?
May be AQT and void in clubs. How will know about pd's AQ or AJ?
Dec. 19, 2019
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For now I only respond to: why it is not a lead problem.
Bidding and lead problems here, are connected with standard bridge played by experts. They are oriented for VOTING, without too deep analysis and an extremely special approach.
Dec. 19, 2019
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