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All comments by Gabriel Fractman
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Thanks to all that answered. It is funny to see that Double is by far the preferred choice, but if you double partner suggested action is 4NT
(see
http://bridgewinners.com/article/view/bidding-problem-2-t1rslzdbv0/)
with the result that you end up in a horrible contract of 5 in a 4-3 fit.

So in this case two rights make a wrong :).
Dec. 22, 2016
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In case someone still wants to see the solution, here it goes. Thanks to Barry Rigal who emailed it first to me and to David and Michael who just gave the hints but clearly has already solved it.

As with many problems, once you see the solution it becomes so easy that you cannot understand how you missed it. But the brain many times goes along the wrong path and it is difficult to bring it back to the right one. In this case, the wrong path is to start with two round of trumps, you should play only one.

The play should go:

- Win A, run 8 (you could also run the J but then you should be careful not to block the suit, so make it simple).
- Ruff two Diamonds,using the A one Club as entry, cash the Q and run the remaining Clubs.

When you play the fourth Club you have in dummy xAQT and East has xKxx; in your hand you still have two other winning clubs and the J (that's the key!). East is then kind of squeezed: if he ruffs you overruff, ruff your losing Spade with the Jand are conveniently in your hand for the final coup. And if he discards so do you and then play the J underplaying with the T to leave again the lead in your hand.
Dec. 22, 2016
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Thank you to all that answered the poll. At the table, I choose to double which looked like the more flexible action. Pass looked to shy given that preemptor's partner was a passed hand.
Partner decided to leave the double with his two minor suit kings and 2-2-4-5, hardly unreasonable, but the normal heart lead would give away the contract since hearts were 5-1 and declarer could discard from his doubleton.
So full marks to Kieran who anticipated this possibility.
Not to say that 4NT should be the bid (partner could have 3-2-4-4 or even 3-3-4-3 with a spade honor), but it was a point I should have considered.
Dec. 21, 2016
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Thank you for the hints, I also already got the solution through some private message. Have to admit spent most of the flight back from Barcelona to Madrid thinking on the problem without success :).
Still people may enjoy working through it!

Nice to confirm that Sherlock Holmes was right.
Dec. 19, 2016
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