Join Bridge Winners
All comments by Ilan Wolff
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Yes, you are right about board 4. Thanks for pointing it out. Regarding the grand slam auction, I think west thiught 5♥ was exclusion, but east thought it was a cuebid.
May 10
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Deleted
May 10
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Are there still plans to introudce a rating system which is not purely cumulative but moves up and down based on results to complement masterpoints?
Feb. 19
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My partner was the one who played jack of diamonds. I think it was a nice play as it gave declarer something to think about and a chance to go wrong, even though as Mike points out declarer should and did get it right.
Jan. 14
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Thank you all for the help! There's a lot of useful information here that I think will really strengthen the application.
Jan. 5
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Thank you, can you explain number 6? I'm curious
Jan. 4
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First step is written, and if we get through that we'll need an oral presentation
Jan. 4
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Extremely helpful,thank you!
Jan. 4
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You're right, this could be refined further, but it doesn't seem necessary. The above is likely a very close estimate.
July 19, 2018
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Yes, I think that's right. Thanks for the correction
July 19, 2018
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Dave, given that someone has AKQJ of a suit, I think it is much more likely they have more than 4 than exactly 4. What we want to compare is the number of hands with AKQJ tight of clubs and the number of hands with AKQJ of clubs and more than 4 clubs.

How many hands are there with exactly AKQJ of clubs? Well the first four cards are given to us, so we need to choose nine more. However there is a constraint. None of them can be clubs. Therefore we're choosing 9 cards from 39 options. 39C9=211915132

How many hands are there with AKQJ of clubs and more than four clubs? The first four cards are still given to us, but this time we can choose any of the 48 remaining cards, so the number we want is 48C9=1677106640. However this includes all of the hands with exactly four clubs, so we must subtract those out. 48C9-39C9=1465191508, the total number of hands with AKQJ of clubs and greater than four clubs. Dividing the total number of hands with greater than four clus and AKQJ of clubs by the total number of hands with AKQJ of clubs (48C9-39C9)/48C9=87.4%. Therefore he has greater than four clubs 87.4% of the time and exactly four clubs 12.6% of the time.
July 18, 2018
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Awesome, thank you!
June 26, 2018
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Lol, thanks Mike :)
June 24, 2018
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My agreements after 2H second negative:
2S relays 2NT, then suit bids by opener are non-forcing.
2NT by opener is non-forcing.
Suits at the three level are forcing.
Actually having agreements for this situation makes the 2H second negative much more effective
Feb. 22, 2018
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I had 5-1-1-6 shape, so 3 NT wasn't a consideration. 5C was a claim if clubs split 2-1.
Dec. 14, 2017
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That's what I told him…
Dec. 12, 2017
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It seems to me that another indication that a spade lead is best is that partner could have doubled 2D with a decent 5 card diamond suit.
Sept. 10, 2017
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