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1M-2x-2N 6+card

In 2/1 strength style, 1M-2x; 2M=5 and 2N=6+ seems a good approach, but I could not find out a formalized follow-ups. Please share if you hear any.

Here is my proposal, based on 1M-2C=2+ & 1M-2D=5 method (bid 1M-2D when holding 55 minors).

 

After 1M-2x-2N (6+):

3M = 3

3N = 2 and no 6-card side suit

  Option:

  A further 4C asks whether there are 55 side suits and a singleton, M2-x5-5-1

  There are 2 spots (4D/4H) after 1S open, and there are only two cases other than M/x

  There is 1 spot (4D) after 1H open, and there is only one case (5-card S is out of picture)

3x = 0/1 and 6-card x suit.  A further 3M = 7

3y = 0/1 and 4/5-card y suit (x >= y).  A further 3M = wait, for PD to show 4M=1 or 3N=0

 

Here is the break-down of all possible distributions:

1s 2c 2n:

    3c = 6

    3d = 1-3-4-5 / 1-4-4-4 (•exception)  //  0-4-4-5

    3h = 1-4-3-5

1s 2d 2n:

    3c = 1-3-5-4 / 1-2-5-5  //  0-4-5-4 / 0-3-5-5

    3d = 6

    3h = 1-4-5-3

1s 2h 2n:

    3c = 1-5-3-4 / 1-5-2-5  //  0-5-4-4 / 0-5-3-5

    3d = 1-5-4-3 / 1-5-5-2  //  0-5-5-3

    3h = 6

1h 2c 2n:

    3c = 6

    3d = 3-1-4-5  //  4-0-4-5

    3s = 4-1-3-5

1h 2d 2n:

    3c = 3-1-5-4 / 2-1-5-5  //  4-0-5-4 / 3-0-5-5

    3d = 6

    3s = 4-1-5-3

The 3M wait will further narrow down the distributions by the "//" sign

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