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Bridge Winners Profile for Alvin Bluthman

Alvin Bluthman
Alvin Bluthman
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Basic Information

Member Since
July 23, 2012
Last Seen
17 hours ago
Member Type
Bridge Player

Bridge Information

ACBL Ranking
Bronze Life Master
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Levi Ramos's bidding problem: AT82 KT85 T93 K4
For the redouble. You will bid 4 later, if given the chance. Until then, you need to show a strong hand, and give partner the information that will be forthcoming from the opponents, if you allow them the bidding room. This will help partner play the hand. If the ...
Defend against Barry Crane
Win the jack, and then lead out king, then ace of spades. If you need a fourth round, play it, low. You are trying to signal the king of diamonds or that your club ten can knock out the ace, depending on partner's choice when he gets in.
Oren Kriegel's bidding problem: AKQ753 K83 A7 QT
Assuming the spades ruin, you have seven top tricks. If partner holds the heart ace, you are home. If he holds the club ace, you have a fake finesse (or need AJx) for game. With the club king, you will need partner to hold a half-stopper in diamonds, such as ...
Methods over Lead Directing X
Doubleton club without a stopper. Why not go ahead and respond normally to Stayman inquiry, and bid 3?
How high will you go? Trivia II
4th clue. Before that, didn't understand that we were being asked for the same person (different person for each clue), and that there was a bridge connection. Think that these elements should have been made clear.
TV series "Fargo"
Didn't they play Board 11 twice? At two different tables? No indication that they were I a two-session event.
Gavin Wolpert's bidding problem: AKQJ9 Q43 85 T92
Yes, 2 must be a one-round force. But you don't hold a heart suit worthy of bidding. So, what do you do now? Do you bid 2 anyway, as a(n unagreed) artificial call? Or do you gamble that partner can run the spades in notrump?
ATB - grand slam fiasco from the 1971 Bermuda Bowl
I see the logic in escaping from clubs with the North hand, but why he did not then pass opener's 1 rebid is beyond me. Even so, there are limits to how forcing (four aces?) North's 3 jump could be assumed to be.
Yuan Shen's bidding problem: T43 --- AQJT9642 98
4. I have a six-loser hand opposite a jump shift, with five of my losers in my partner's two suits. I can see partner covering all six of my losers, with a range of possible hands. Given your methods, I would also have started with 2 instead ...
What does this double mean. I have no idea.
To those who think I provided a 1NT opener, I provided a perfectly reasonable 1 opening playing c. 12-14 1NT openers. Don't forget that many of us play different ranges with different partners

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