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Bridge Winners Profile for Andrew Sinclair

Andrew Sinclair
Andrew Sinclair
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Basic Information

Member Since
April 25, 2016
Last Seen
7 hours ago
Member Type
bridge player

Bridge Information

ACBL Ranking
Andrew's personalized 2/1 card
Copy to my cards View/Print
Equivalent of FSF-1round, NMF/Checkback after 1m-1h; 2m-?
After 1-1-2, 2 can be artificial third suit forcing. With the given hand and auction, I'd bid 2NT no matter where the honors are. Partner can bid 3 with exactly 2=3=6=2 (or would partner not raise hearts with (1)-3=6- ...
What Do You Bid Over 2NT
I read your system, and agree with your goals for UP! including the order of the importance of finding fits. Unfortunately, this is a place where UP! can miss what you identified as the first priority fit to find (3 with opener, 5 with responder). With 53 majors as responder ...
What Do You Bid Over 2NT
After 2NT-3; 3-3NT, if opener is (32) in the majors, you can't find out if you have a fit below 3NT.
Lebensohl after opps show both majors
Over 2, 2 is to play. Over 2 or 2 we play uvu, so 2 shows clubs and 2 shows diamonds, Inv+, and double is to penalize. Over 2, 2, and 2, Lehbensohl is on: 2N relays for a signoff. Direct ...
David Parsons's bidding problem: 52 KQ942 KQT632 ---
Is that standard or a specific agreement you have? It seems like many people would play that as an invitational splinter.
Alan Shillitoe's bidding problem: JT763 K9 K7642 6
If you wanted to play 4 regardless of what partner has, you need to use Texas transfer. Jacoby transfer then 4M is an invite to slam exploration.
Peg Kaplan's bidding problem: Qxxx AJTxx ATx x
Surely I have a systemic bid to make here. I make whatever that bid is. For my answer to this poll, I assumed the same system I use when partner opens a precision 2 showing 4=4=1=5 less one card anywhere.
Super-accepting after 1NT opener
Some people play doubleton super-accepts. Why not transfer doubleton super-accepts? 2M+1 = club doubleton, 2M+2 = diamond doubleton, 2M+3 = oM doubleton. 3M-1 = Nothing to protect, I.e. Axxx Axx Axxx Ax and 3M = 4333.
Ron Steele's bidding problem: A9 AKT 654 AKQ95
If you don’t want to stop in 3, you should upgrade this to a 2 opening.
Peter Lipp's bidding problem: AQJ QJT6 KQJ QJT
If you’re not playing Jacoby 2NT you’re not playing SAYC but a different variation of Standard American.

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