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Bridge Winners Profile for Bogdan Agica

Bogdan Agica
Bogdan Agica
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  • 3
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Basic Information

Member Since
May 29, 2012
Last Seen
Nov. 18
Member Type
Bridge Player
about me

That awkward moment when, after perfectly executing a double squeeze, you realise that 5-3-2-2 is not a valid distribution.

Country
Romania

Bridge Information

Favorite Bridge Memory
That awkward moment when, after perfectly executing a double squeeze, you realise that 5-3-2-2 is not a valid distribution.
Favorite Conventions
Mixed raises
BBO Username
pashadia
ACBL Ranking
None
Sorry, this user has no cards yet.
Gonzalo Goded's bidding problem: T853 KQ6 T932 T4
I'm definitely not passing. Passing would mean that I believe partner to have HH in spades, and I trust my partners to not have that. Between 3D and 2NT, I'll choose 2NT. I want to bring hearts into the picture, partner could well have 5 of them.
Yuan Shen's lead problem: K5 AT942 JT QJ97
I'm was curious as of how many will choose the A of for their opening lead --apparently it's only me. For sure it's safer to lead the A and the switch to clubs when it's right
The Worst Agreements in Bridge
Even if you're right about when they come up, it's only half the story. What about the missed opportunities of using that bid for something else? What about the negative inferences (or lack there of) of other bids? I think these cases are much less quantifiable, and really ...
Roger Lee's bidding problem: AQJ872 AK74 AKJ ---
Eric, what is help ? Is a singleton help? How about xxxx ? How about xxxxx ? The only time asking for help wins is when you find the Q (but not the J). And is partner supposed to move beyond 4 with xxxx Qxx xx xxxx ?
David Loeb's bidding problem: --- T AKJT42 AKQT97
So that would mean an exclusion in 5 then bidding 6 ? :)
Vlad Posea's bidding problem: QTxx T9xx QJxx x
Let's see. This is likely a 17 tricks hand. If partner has a good 5 card major, *maybe* he would have bid it the first time around. The opponents are *likely* to have a 9 card fit, but it's not cast in stone, responder could easily have 3325 ...
Vlad Posea's bidding problem: Kxx Axx Axxx AQx
Oh, sorry. 4 it is.
Vlad Posea's bidding problem: Kxx Axx Axxx AQx
I don't know the system, but I assume partner is unlimited -- and that we are in a game force. In this case, I think 3 is hugely better than 4, especially with a 7 control hand.
Bogdan Agica's bidding problem: KQ9852 3 AT75 A8
At the table, I phased out and bid 4, not seeing other real possibilities, and, perhaps subconsciously, tring not to reveal opener's hand further. Opener had AT JTxx KQJx xxx, making 11 tricks in spades and 12 tricks in diamonds. The bidding could have went 1NT - 2 ...
Bogdan Agica's bidding problem: KQ9852 3 AT75 A8
I posted in the description, 1NT = 10 - bad 13
.

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