Join Bridge Winners

Bridge Winners Profile for David Boxley

David Boxley
David Boxley
  • 6
    Following
  • 4
    Followers
  • 29
    Posts
  • 0
    Favorites

Basic Information

Member Since
March 9, 2012
Last Seen
33 seconds ago
Member Type
Bridge Player
about me

Haven't played seriously in over 25 years.

Country
United States of America

Bridge Information

BBO Username
dboxley
ACBL Ranking
None
Sorry, this user has no cards yet.
Robert Thorstad's bidding problem: J KQ75432 872 J4
3 gives your partner more room to discover if there are two quick losers in any suit. If you are saying that 4 absolutely denies controls in either minor then I would agree.
Simon Weinberger's bidding problem: KT87 9 KJ6 QT985
I'm assuming that 2 by partner would show at least a good 4 card suit so that he has not denied 4 of them. Otherwise I just bid 3.
Hanoi Rondón's bidding problem: A87xx Q AKQJ KQ8
When I passed I wasn't really expecting you to reopen, I was willing to defend 4. If you balance at the 4 level with garbage then you deserve whatever result you get. Unfortunately I have to share in that result. I notice you did not give an example ...
Mike Cassel's bidding problem: A KQ73 AQT943 54
Although 3 is not ideal with a stiff A, both 4 and 4 are inferior for different reasons: 4 should show better diamonds 4 should deny shortness in a side suit And most importantly, both of these calls keep partner from conveniently showing a club ...
Steve Myerson's bidding problem: 765 AT75 9732 AK
I think Kevin is saying that he wouldn't be adverse to partner trying for slam. I wholeheartedly agree.
John Samsel's bidding problem: AKQ63 653 Q6 Q42
He may not HAVE to pass it but he always will... I also voted for 4 but I'm not kidding myself that it is an odds-on favorite.
Buddy Hanby's bidding problem: AK9642 Q9 AT65 A
Well, that's my answer and I'm stickin' to it.
Hanoi Rondón's bidding problem: A87xx Q AKQJ KQ8
Probably missed 7 but I can't think of a way to find out. As for passing 4, I don't see any alternative.
Christopher Monsour's bidding problem: K AKJT6 AJ2 T864
Good one, Paul :) I suspect partner is something like 3253 with xxx in spades and we belong in diamonds but I'm not sure enough to bid 4. Only one person voted for 4, I kind of wish it had been me.
David Boxley's bidding problem: K62 Q9732 AK4 T2
That's really what I was getting at, what is the meaning of the 5NT bid? It shouldn't be GSF because no suit is agreed or implied. So in this sequence is it PAS or quantitative for 6 or 7? I have trouble believing that partner couldn't come ...
.

Bottom Home Top