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Bridge Winners Profile for David Parsons

David Parsons
David Parsons
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Basic Information

Member Since
Nov. 6, 2015
Last Seen
Jan. 13
Member Type
Bridge Player
about me

Actuary, Ranked Chess and Othello Master, now retired and studying Bridge.

Bridge Information

Bridge Accomplishments
Recently, 4/75 at the District 3 NJ Regional, 1/57 at the Eastern States Regional Open Pairs in NYC, 42/364 in Silodor at the Spring NABC in Philly.
Regular Bridge Partners
Paul Frean, David Libchaber, Irving Gewirtzman, David Carter
Member of Bridge Club(s)
Honors in NYC
Favorite Conventions
Not a convention, but I love New Losing Trick Count (NLTC) for hand evaluation.
BBO Username
parsonsdav
ACBL Ranking
Ruby Life Master
Parsons Libchaber
Two over One (Larry Cohen's Style)
Copy to my cards View/Print
David Parsons's bidding problem: AJT532 75 Q2 K62
Partner doesn't get another bid, does he?
David Parsons's bidding problem: QJ3 Q75 KJ732 QJ
Jack, I really value your input. Would you pass any 12HCP hand at MPs? If so, is this an exception because it has five diamonds? Thanks!
What do you play at trick two at Matchpoints?
Not on my screen. West is on the left and dummy (North) is on the top.
David Parsons's bidding problem: AQJ8 Q5 J9875 Q7
I would say that it is certainly close. One can foresee a heap of trouble when the bidding goes: 1 1 2 4.
David Libchaber's bidding problem: 83 A4 72 AQT8543
Indeed, perhaps Libchaber was not talking about our agreed system but another hypothetical system?!
David Parsons's bidding problem: KQ3 T54 AQ93 K32
I stand corrected -- I ran a DD simulation of this hand, constraining partner to four spades and 12-14 HCPs. 4 makes 65% of the time.
David Libchaber's bidding problem: 83 A4 72 AQT8543
1 2NT
David Libchaber's bidding problem: 83 A4 72 AQT8543
Why unplayable? Four of a minor can be the resting place only if 3NT is explored but found unviable. So, the uncontested auction: 1 2 2 3 3 4 P is possible, for example.
David Parsons's bidding problem: KQ3 T54 AQ93 K32
The problem is, David, you are probably not going to make 4 even on a 3-4 fit because LHO probably holds at least four spades and the long hand is ruffing hearts.
David Parsons's bidding problem: KQ3 T54 AQ93 K32
East happens to be Joe Grue on the bidding we're discussing (really, it was!).
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