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Bridge Winners Profile for David Parsons

David Parsons
David Parsons
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Basic Information

Member Since
Nov. 6, 2015
Last Seen
an hour ago
Member Type
Bridge Player

Bridge Information

Bridge Accomplishments
Recently, 52/388 in Wernher Open Pairs for my first Platinum points.
Regular Bridge Partners
Paul Frean, David Libchaber, Irving Gewirtzman, David Carter
Member of Bridge Club(s)
Honors in NYC
Favorite Conventions
Not a convention, but I love New Losing Trick Count (NLTC) for hand evaluation.
ACBL Ranking
Silver Life Master
Parsons Libchaber
Two over One (Larry Cohen's Style)
Copy to my cards View/Print
David Parsons's bidding problem: J7 Q2 AKT762 J98
Jordan, my note about the "majority NYC style" was in response to your comment "I thought everyone played this in 2/1," which comment appeared to not be oriented towards BWS. I have no idea what BWS meant about "invitational" but I can't imagine it's invitational to game ...
David Parsons's bidding problem: Q5 AKJ8653 KT4 6
Yes, 3 is invitational.
David Parsons's bidding problem: J7 Q2 AKT762 J98
The large majority of players in NYC (that is where you and I both live, I see) play Bergen raises.
David Parsons's bidding problem: J7 Q2 AKT762 J98
I would think that the BWS description is that of a "fit-showing jump," indicating a game invitational hand, with at least a three-card fit, and five+ diamonds. Some might play that such a jump would require four hearts. Does anyone know the "number" of cards for the major-suit support ...
David Parsons's bidding problem: AQJ432 AK AJ 732
Richard, that "unlikely to exceed 40%" comment is a good one, and something I should have considered. Thanks!
David Parsons's bidding problem: AQJ432 AK AJ 732
If you have nine trumps non-vul, it's very unlikely you'll be doubled at the three level. That's the law protection.
David Parsons's bidding problem: AQJ432 AK AJ 732
I would like to think that I would compete to the three level on 3=4=4=2 distribution and zero HCPs, NV-vs-Vul in balancing position, when I know we have a nine-card spade fit and partner rebid 2 freely.
David Parsons's bidding problem: AQJ432 AK AJ 732
Very interesting way to handle this problem -- I like it!
David Parsons's bidding problem: AQJ432 AK AJ 732
Question for the doublers: From the bidding, it's likely that partner has a doubleton club and doubleton spade, and no HCPs. If partner has three spades, he should bid 3 himself (per LOTT) even over your pass. If you double, partner will almost certainly say 3 with ...
David Parsons's bidding problem: AJ6 J8 JT984 A32
A followup -- Partner was 1=4=3=5. 3 goes down one (for 100), while 4 makes. 4 is the matchpoint winner.
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