Join Bridge Winners

Bridge Winners Profile for Erik Hansson

Erik Hansson
Erik Hansson
  • 73
  • 13
  • 14
  • 0

Basic Information

Member Since
May 17, 2016
Last Seen
4 hours ago
Member Type
Bridge Player
about me

Swedish junior, 19 years old


Bridge Information

Favorite Bridge Memory
Winning the youngsters European Championships by 1 imp in 2017
Bridge Accomplishments
U21 World Champion 2018 and U21 European Champion 2017
Regular Bridge Partners
Castor Mann
Favorite Tournaments
The Swedish Bridgefestival in Örebro
Favorite Conventions
Gazilli and Jacoby 2NT
BBO Username
ACBL Ranking
Sorry, this user has no cards yet.
Martin Lindfors's bidding problem: 73 J9543 KQ984 7
This is a fit jump to 3H. If you jump to 4D and the opponents bid 4S, what now?
Martin Lindfors's bidding problem: Q4 AK875 K2 KJ73
3S is searching for the best game
Martin Lindfors's bidding problem: 32 J972 J652 963
Without a suit there is no bid
Martin Lindfors's bidding problem: 5 AKQ865 QT7 QJ6
Seems like partner has 2*H and 3-4*S based on the bidding, since he didn't bid 2S/3H
Martin Lindfors's bidding problem: 3 AT72 9875 A952
3S+4H seems about right. I dont like the 3C bid, what do I do when p bids 3D/3S? I guess it worked out this time... I'd rather show both m's with perhaps 3S?
Allan Simon's bidding problem: T98 AQ6543 A97 T
2H=8-11 and a direct jump shift is 3-7. No point in playing 3H as INV. When partner has a minimum and singelton heart it's going to be a struggle to take 9 tricks.
Erik Hansson's bidding problem: ATxxx Q AKxxx Ax
Partner is known to hold 1C. He shouldn't have xxx or Hx in spades since he didn't bid spades a single time. He shouldn't have Hxx in diamonds either because he bid 4H (unless he has a very good heart suit). So 2-7-3-1 with xx in spades ...
Smolen over 2NT
Martin, if you play normal transfers after 2N it's possible to find the major fit with a 3M+1 accept bid as 5=2 M's. So 2N-3D-3S= 5S & 2H and 2N-3H-3N= 5H & 2S
Martin Lindfors's lead problem: AK7643 A65 732 4
Even if you can give partner a spade ruff, there is no hurry since you have the ace of hearts. Partner usually has 2cH if he has 1cS. It's very unlikely that partner has 1-1 in M's.
Martin Lindfors's bidding problem: KQ9874 KQT7 K KJ
He shouldn't show 10-12 with three aces.

Bottom Home Top