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Bridge Winners Profile for Floyd McWilliams

Floyd McWilliams
Floyd McWilliams
  • 16
    Following
  • 19
    Followers
  • 166
    Posts
  • 46
    Favorites

Basic Information

Member Since
Jan. 5, 2012
Last Seen
an hour ago
Member Type
Bridge Player
Country
United States of America

Bridge Information

Favorite Conventions
I named a cat after Namyats, but it's not actually my favorite convention.
BBO Username
floydm
ACBL Ranking
Ruby Life Master
Floyd and Adam
Strong Notrump 2/1
Copy to my cards View/Print
Adam Meyerson's bidding problem: K4 Q6 AKJ7 J7652
"Kiss partner, but pass." - Ira Rubin
Partner Plays Barbu
The full hand: I (third hand) held 543 K75 AQKT9 Q2 Declarer AKJT9872 9 J76 K On partner's A lead I considered dumping the king to get a diamond lead but wasn't sure if that was really what the king would mean, so I played the 7 (UDCA ...
Claim ruling poll
Declarer should not claim if he might need to "think for a bit". The thinking should be completed before the claim is made! The frame of mind in which one claims should not be "Well I guess I have this many tricks but if something weird happens I can probably ...
Partner Plays Barbu
So the 5 would be suit preference for clubs? How does partner encourage more hearts? And why can't partner raise on Kx?
Floyd McWilliams's bidding problem: 93 AJ53 A72 JT93
That was more unanimous than I expected. Off to part 2: http://bridgewinners.com/article/view/bidding-problem-2-c1hfmcasa4/
Bob Okker's bidding problem: Q86 652 J65 AKT8
I've learned though experience that even 4333 11-counts are an underdog to make game opposite 12-14.
Stéphane Turcotte's bidding problem: Axx AKJx AJx AKJ
Not that it really matters to this problem, but I play a system over 2N which I have always known as Romex Stayman, and in that system 3 shows 4 or 5 (3) asks. Stephane, do you have a reference for your Romex Stayman system?
Winston Chang's bidding problem: QJT654 9 KT92 K3
What was the double of 1?
Floyd McWilliams's lead problem: J863 A42 JT85 J3
Declarer bid 3N. The heart void would have to be in dummy. Which is possible though you'd think there would have been a splinter / control bid at some point.
David Corn's bidding problem: JT4 6 J952 KQJ74
I believe this covers your possible options: https://imgflip.com/i/1xzmfs
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