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Bridge Winners Profile for Itzik Ezra

Itzik Ezra
Itzik Ezra
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Basic Information

Member Since
Sept. 19, 2013
Last Seen
an hour ago
Member Type
bridge player

Bridge Information

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Kinpin Chu's bidding problem: T9863 KJT95 --- KT7
A very simple hand. 4d. If patner is broke tell his: To make a game we need shape and points. I brought the shape your duty was to provide the points.
Rohit Gupta's bidding problem: AK AQJ65 AJT43 6
Well i guess we endplayed ourself. Maybe 4c over 2h was better.
József Szikszai's bidding problem: KQJ2 AK64 A72 K9
Holding 4s and 2h he can't know that opps have a fit. (though they might have a fit and even likely to have a fit). And also he can't "know" that you have 8 cards in sp as i am not so sure that the second x promises ...
József Szikszai's bidding problem: KQJ2 AK64 A72 K9
If partner knows to bid 2s with something like XXXX XX XXXX XXX then i guess he knows more about brige than me. Would he also know to bid 2s with something like 10XX XX XXXX QXXX ? If so then 2sp by south might be wrong as partner can't ...
József Szikszai's bidding problem: KQJ2 AK64 A72 K9
Just one more. please . Partner is favorite to have 4 cards in sp and short hearts (0-2) so 2sp and 2h wil both have a play and maybe east will have 3 hearts and will go to 3h. Pass will be correct usually only when both 2h and 2s go ...
Paul D East's bidding problem: 4 AKQ7 QJ9 AJ743
The 2 last hands caontain cards that we also have Q/J of doiamond. The first 2 hands are very good examples. And i agree that 6nt will be wrong with diamond lead through the ace. 6S is much better. That is why i bid 5s and i think partner ...
Paul D East's bidding problem: 4 AKQ7 QJ9 AJ743
I meant this by "and though...". But taking all suits in account i thinks the chances for a hand like it are very small. Much smaller then HX in clubs which apriory has a chances of 2/8*6/7 + 6/8*2/7 = 0.2143+ 0.2143 = 0.42863 ...
Paul D East's bidding problem: 4 AKQ7 QJ9 AJ743
What are the chances that patner will have a hand like this? WHen i try to construct a hand that fits partner's bidding i try not to put singletom nhonors nor 2 cards honors like KQ especially 2 specific cards. Here there are 8 cards in clubs and the ...
Paul D East's bidding problem: 4 AKQ7 QJ9 AJ743
If we have 2 losers in sp we probably can't make a slam. I bid 5sp and partner is expected to use his judgement. If partner has a sp loser and ace of diamond i prefer him to declare for example: AKJ10XXX XX AXX KX 6nt from our side ...
John McWhinnie's bidding problem: KQxx KTx x AQT9x
2h. If it is right to bid 1s with this shape then there is no reason 2h now will be stronger or weaker than over 1h Else you can't bid 1s with that shape without the strength agreed and you lose 4-4 sp fit..
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