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Bridge Winners Profile for Kieran Dyke

Kieran Dyke
Kieran Dyke
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Basic Information

Member Since
Aug. 25, 2015
Last Seen
5 minutes ago
Member Type
Bridge Pro
about me

Professional based in London.


Numerous national wins in Australia and now a few in England, most recently the Brighton Swiss Pairs.

Bronze medal, 2015 European teams.


I play on BBO as Woozle.

United Kingdom

Bridge Information

Favorite Bridge Memory
Beating Monaco in the Round of 16, 2015 European Teams, Tromso.
Bridge Accomplishments
Bronze medal, 2015 European teams. Numerous national events in Australia and England.
Regular Bridge Partners
Fiona Brown, Justin Howard, Michael Byrne. Partners back in Australia included Ron Klinger, Peter Gill and Ishmael Delmonte.
BBO Username
ACBL Ranking
Sorry, this user has no cards yet.
Nick Fahrer's bidding problem: K7 AKJ54 AJ763 6
2D, then another move after partner's minimum rebid.
Emanuel Evacic's bidding problem: --- JT876 K874 A764
I assume that the 2H bidders are aspiring to play a slam in a partscore.
Emanuel Evacic's bidding problem: --- JT876 K874 A764
Steve, for this club holding to suggest offence, partner will need to be short. In that case, he's not passing out 2C.
David Yates's bidding problem: A7 JT2 3 AQJT953
That's ridiculous. His partner doubled, showing spades. He'll bid 3S on any hand with five hearts and four spades except the most awful. It's not like he bid 3S with his partner passing. If he really was likely to have something like this, your partner would know ...
Craig Zastera's bidding problem: KQ92 952 AJ32 A6
Double, but if he bids clubs he can play there.
Winston Chang's bidding problem: AQJ J653 Q7542 9
Whichever out of double and 1S doesn't show spades.
Winston Chang's bidding problem: 952 AQ87 T763 K9
Let me get this straight - I can't invite game.
Jon Gassaway's bidding problem: K53 863 AJT8 AK4
This sounds like something that should have been considered before you decided that double shows spades and 2D is non-forcing.
Winston Chang's bidding problem: AJ5 AT94 K86 Q97
2H, followed by 2NT.
David Yates's bidding problem: A7 JT2 3 AQJT953
Surely the odds are substantially altered when 4S is doubled.

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