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- How to calculate the odds
- 8 means the remaining cards (in addition to the 4 spades and the Ace) in West's hand.
- How to calculate the odds
- 4 spades out of 5, 8 remaining cards out of 20, excluding the already placed Ace. Addition: This gives C(5,4)xC(20,8) = 5x20!/(8!x12!).
- How to calculate the odds
- As always, there are different ways to do the calculations. Here is one focusing on the number of combinations of the various cases. Assume West has the Ace of interest. Then there are C(5,4)xC(20,8) combinations where West has 4 spades, and C(5,3)xC ...
- Another Question for Mathematicians--well...Statisticians
- I can repeat my calculations for 26 cards (2 hands) instead of 13 cards (1 hand). This gives Var(X) = 16/17 and Cov(X,Y) = -4/51, which for both is an increase by the factor 4/3. Thus, the result sqrt(1160/51) is obtained. Does Helene have ...
- Another Question for Mathematicians--well...Statisticians
- The honor card distribution is a multivariate hypergeometric distribution. The following expressions follow from formulas for that distribution (see, e.g., Wikipedia). The variance of the number of honor cards of a given rank X (J, Q, K or A) is Var(X) = 12/17. There is a negative correlation ...
- Question for Mathematicians
- Good guess.
- Question for Mathematicians
- To obtain my results, I have used Frederick Frost's "bridge odds complete" from 1971. It is known to contain some errors, but hopefully not in the figures I have used. The result depends on what honor cards your 7 HCP contains. AK gives a different result than QQQJ. For ...
- So...now is time to consider an electronic Bridge Bulletin & Daily Bulletin?
- ACBL already applies this to "foreign" addresses. If you want the printed issue, you have to pay extra. I don't, so I only have access to the on-line version. Addition. "I don't" refers to "pay extra", I would like to have the printed version.
- Google Knows Bridge
- Around 1975 I wanted to generate deals for bidding practice during the forthcoming summer. I had access to a Honeywell H-316 computer with 16K of memory which could be programmed in FORTRAN using punched tape. The problem was that I didn't have a random number generator, but then I ...
- Zia would know what to do
- Yes, that's the main advantage of trying the drop when spades are 4-4. When they are 5-3, the entry is not needed for a heart finesse.

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