The law of total tricks says that on average the two sides will take 21 total tricks (10 card club fit their way + 11 card spade fit our way). Bidding 5♠ is frequently correct. It just wasn't the winning choice on this hand.
I might have doubled just ...
I made the matchpoint choice of 2♣ stayman. I was going to bid 2♥ over 2♦ from partner (as garbage stayman), pass if partner responded 2♠, or raise to 4♥ if partner responded 2♥.
Partner responded 2♥ and I placed them in game ...
I chose 4♠ and we partner played it there.
The opponents led 2 rounds of hearts, and he played a club to the jack, which held. The clubs split 42 (with the length in front of dummy's 5 ...
Partner elected to bid 5♠ with this hand, and this was unfortunately doubled by the 2♣ bidder.
This went down 1 for -200 and a poor result when RHO won trick one with the ♣ A, and played ...
I chose to open this hand 2nt, since I held cards to protect on major suit leads, held a decent potential source of tricks in the diamond suit, and the opponents are not likely to find a double dummy club lead if the auction goes something like 2nt-3nt with my ...
I chose 2♠ instead of the takeout double b/c:
1) Partner knows that I only have a 4 card suit (I did not transfer to spades last time), therefore if they only have a doubleton they will take another bid (2nt or 3 of a minor).
2) I ...
I chose to make the slightly unusual bid of 3♠. The bidding proceeded:
(P)-P-(2♦)-2S-(3♥)-3♠-(4♥)-P-(P)-dbl- All Pass. We set this 2 for +500.
The Flannery bidder was understandably surprised when they held ♠ J10xx, and ywt their ...
I made the only lead to allow declarer to make 5 for a zero.
Silly me I thought to lead the ♦ Q.
Turns out that LHO forgot what they were playing and meant 2♦ to be natural. In addition, the suit that they overcalled was A107xx, and the ...