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Bridge Winners Profile for Lynn Harris

Lynn Harris
Lynn Harris
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  • 8
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  • 11
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Basic Information

Member Since
July 17, 2013
Last Seen
4 hours ago
Member Type
Bridge Player
about me

Marketing professor for 40 years.  Last 30 at Shippensburg University.  Golfer who used to be good, but has declined.  Times when I think I should be playing golf when I am playing bridge, and times when I think I should be playing bridge when I am golfing.  Love to think of bidding sequences which are available. I like to put pressure on the opponents (and sometimes on partners).

Country
United States of America

Bridge Information

Favorite Bridge Memory
How good the games were at Paul's B.C. in Culver City. Winning a whole master point was great.
Member of Bridge Club(s)
Harrisburg Bridge Club
Favorite Conventions
Astro Cue bid, Jump Q bid to indicate limit raise+ (simplifying Q bid meaning)
ACBL Ranking
None
Copy of Lynn Harris Carl Huber, Jr.
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Ken Meyer Lynn Harris
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Barry Gorski- LynnHarris
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Lynn Harris- Jane Ball
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Lynn Harris - Bill Young/ Deb Hoveland
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Lynn Harris- Linda Ivanoff
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Lynn Harris- Linda Ivanoff
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Copy of Mel Lubart, Lynn Harris
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Copy of Mel Lubart, Lynn Harris
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Lynn Harris Vernon Hester
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Sathya Bettadapura's bidding problem: AK64 7 KQT42 J96
Abstain. Do not agree with 2S. This is a competitive auction and is very unlikely to stop with a 2S bid. Instead of bidding 2S, we should X the 2D bid by E. We can bid 3S after a 3H bid by E or W and might be able to ...
Martin Lindfors's bidding problem: KQ9874 KQT7 K KJ
Certainly is as you should well know. Unless you are like Richard and have a better approximation for HCP values (e.g., 4.3 for an ace), the other cards in your hand influence your value. AT9 instead of A32 can make a major difference in the play. 3 or ...
Jim Priebe's bidding problem: KJT76 KQ92 AK43 ---
5H. How good is your hand in these two suits? 5C (2 votes) only indicates shortness in C. 5H is very specific. 4 votes for P which essentially gives up on a slam.
Martin Lindfors's bidding problem: KQ9874 KQT7 K KJ
Yes. If they would play 3C as 10-11 hcp after 1NT instead of 10-12, there would be no way they could possess 3 aces, and we would stay out of a slam. That is one option that does not make sense. Again, here hcp do not provide much info where ...
Martin Lindfors's bidding problem: KQ9874 KQT7 K KJ
So with 3 aces it is 13 hcp. still a minimum.
Gordon Rainsford's bidding problem: KJ542 A87 AT5 QJ
5C. Solidifying the C suit and showing at least a secondary H control. If partner happens to bid 5D will happily bid 5H.
David Lin's bidding problem: A75 2 63 AKQJ862
Maybe you would prefer to go down, but I doubt that your partners enjoy it. You usually have 8 tricks but you better figure out how many partner has.
Martin Lindfors's bidding problem: KQ9874 KQT7 K KJ
For what reason? Is there some law?
Jordan Lampe's bidding problem: 9742 J3 A4 KT985
1S. This should be almost unanimous as there is no good alternative.
Marten La Haye's bidding problem: 4 AT6 AQ654 AKJ8
Abstain. Do not like cue-bid of 3S as it takes too much bidding space and does not indicate what our hand contains. Yes, it is forcing but partner is supposed to bid 3NT with a stopper. At this time, 4/8 panelists then bid 4C. Is that forcing to game ...
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