Join Bridge Winners

Bridge Winners Profile for Mark Bartusek

Mark Bartusek
Mark Bartusek
  • 0
    Following
  • 10
    Followers
  • 8
    Posts
  • 0
    Favorites

Basic Information

Member Since
Sept. 19, 2015
Last Seen
18 hours ago
Member Type
Bridge Player
about me

Retired software engineer - Electronic Warfare (F-18 Superhornet) with Raytheon / Hughes Aircraft Companies

Texas Hold-em and Pot-limit Omaha player

Long-time owner of 1994 Mazda twin-turbo RX-7 modified to 400hp

 

Country
United States of America

Bridge Information

Favorite Bridge Memory
Partner and I played 3 quarters directly against Meckstroth/Rodwell in the Vanderbilt KOs. We got the best of them in 2 of the 3 quarters at our table and we knocked them out of the event!
Bridge Accomplishments
5th overall in NABC Blue Ribbon Pairs, multiple 9-16 overalls in Vanderbilt / Spingold events, 1st overall in 0-5,000 and 0-10,000 NABC pairs (Note: played each event ONLY once), 4th overall in NABC Fast Pairs, 4th overall in NABC North American Swiss, 1st (twice) and 2nd (twice) in the annual Bridge World MSC Contest (out of 6 attempts) and on their expert panel for 2.5 years, ACBL National Appeals Committee co-team leader for 15 years.
Regular Bridge Partners
John Jones, Michael Schreiber, Jeff Miller, Carreen Hinds, the late Marshall Miles, Rick Panter, Will Beall, Jack Yeasley
Member of Bridge Club(s)
Santa Barbara, CA
Favorite Conventions
Kaplan Inversion with Flannery 2D
BBO Username
bart_rx7
ACBL Ranking
Emerald Life Master
Sorry, this user has no cards yet.
Mark Bartusek's bidding problem: A98 AQT KQ86 KJ6
Double (by partner) would show values and an interest in competing (allowing you to either pass or bid a suit). The actual bidding question delves into what patterns you expect partner to be and what your sides prospects are.
Rohit Gupta's bidding problem: AQ6 AKJT95 A76 8
I would say that 5 guarantees 6+ support because you eliminate the opportunity for partner to bid a natural and non-forcing 4 over a 4 raise. And whether you have 0, 1, or 2 s also plays a role.
Which is 4SF to game?
Clearly this question generates added complexity if you’ve tacked on XYZ to this auction. I believe what the OP is simply trying to ask is “what makes sense in a Walsh context without XYZ, where 4SF is required to force to game”? Thus, to answer this carefully worded question ...
Daryl Fisher's bidding problem: 9 J98762 AK942 5
4NT. Then over the expected 5 call my 5 correction will be a slam try (stronger than an immediate 5 bid by me)
Gary Ansok's bidding problem: J76 AJ6 AT876 85
I play XX as showing “exactly a doubleton” in partner's suit along with decent values. I can then usually leave any follow-up action to partner, if he so desires. If holding shortness in partner’s suit then you probably would either bid another suit or trap pass. Some players ...
Chris Chen's bidding problem: KJ9 AKQJ9865 Q 2
For those partnerships on firm ground a 5 bid here would be “Super Gerber” since with s one would have either raised 3 to 4 or else bid 4 right now setting the trump suit.
Winston Chang's bidding problem: J4 K5 AK9742 T92
This is why I dislike the invitational 3-level jump shifts unless holding shortness in partner’s major. One loses a 6-2 major suit fit too often (and sometimes a 5-3 fit when partner opens 1). Michael Shuster even reminded us in an email a while back that in ...
Range Stayman after a Protective 1NT?
As I’ve mentioned in other threads I strongly recommend Mike Lawrence’s simple and straight-forward system: 1/1 - P - P - 1NT = 12-14 (with 15-16 you double and rebid 1NT) 1/1 - P - P - 1NT = 12-16 (with Range Stayman) NOTE: Many years ago in The Bridge ...
Jakob Kristinsson's lead problem: xx xx AKxx Kxxxx
I’m always wary of trusting the opponents bidding too much. Leading a club is trying to defeat the contract “2 non-vul tricks”. I’m content with down 1 and I don’t want to risk a catastrophe… e.g. 1) North might have been ashamed of his hand or ...
Jakob Kristinsson's lead problem: xx xx AKxx Kxxxx
King (expecting count from partner). I'm surprised that there are 14 leaders and only 1 other leader. We need a trick to defeat the small slam (certainly not getting a heart trick). I can always switch to a club at trick 2 to get the ...
Not following anyone yet
.

Bottom Home Top