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Bridge Winners Profile for Ned Kohler

Ned Kohler
Ned Kohler
  • 4
    Following
  • 13
    Followers
  • 161
    Posts
  • 14
    Favorites

Basic Information

Member Since
May 1, 2011
Last Seen
14 hours ago
Member Type
Bridge Player

Bridge Information

Bridge Accomplishments
A few Plat points, some regional wins
Regular Bridge Partners
Sherryl Buchler
Member of Bridge Club(s)
Doty Bridge, AZ Bridge,Intempo
ACBL Ranking
Gold Life Master
Copy of SKB & Ned
Copy to my cards View/Print
Howard Sandler's bidding problem: Q8763 AJ8 --- KQ942
Bidding is so much easier when you don't start off with a lie.
Rae Murbach's bidding problem: 76 AKT8752 A Q53
Hey, it's a 2.5 bid. Ya pays yer money and takes yer choice. Since I would still bid 2 if my two small were anywhere else, I can't bring myself to go low.
James Huntington's bidding problem: QT9642 K76432 5 ---
Plan is to pass, then bid cheaply when X'd. If undoubled in 2N, will be happy. If I get to defend, ecstatic.
Steve Kitching's bidding problem: AQJ5 AKT62 75 J3
I would bid 2 playing 2/1. Don't know if that is correct in ACOL w/4CM or not.
Dire Straits: CAN you be a Swing Sultan?
David, is CAMCE an adjunct to CAMRA? Perhaps there is a correlation between the amount of RA consumed and the amount of CE spoken and/or typed.
Mimi Bieber's bidding problem: 432 AJ8 Q9432 74
This is strictly on methods. You have a mixed raise. I like to use 2 as I presume the lone 2 voter intends. With some partners this is a 3 bid (described as a Standard American 2 bid). With most partners who play 3 as ...
Rohit Gupta's bidding problem: JT9753 4 A98 AJ3
1 definitely but least of evils rather than not close. The texture in swings the decision.
John Torrey's bidding problem: 52 73 Q754 KQT84
This type of hand is why I like 1m-2 to be a mixed raise. You show values so that Opener can freely bid 3N with an appropriate hand and is warned off over 3m. There is no temptation to stretch to a sub-min limit raise or bid an ugly ...
Donald Lurie's bidding problem: QT983 KQ854 K6 3
In our region, both 2 and 2are natural. So X is it. CORRECTED
Stefan Olausson's bidding problem: 752 QJ96 82 AKQ7
The cheapest bid in a forcing auction can never show extra values.
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