Join Bridge Winners

Bridge Winners Profile for Robert Schachter

Robert Schachter
Robert Schachter
  • 13
    Following
  • 12
    Followers
  • 84
    Posts
  • 0
    Favorites

Basic Information

Member Since
Feb. 26, 2014
Last Seen
7 hours ago
Member Type
Bridge Player

Bridge Information

ACBL Ranking
None
Sorry, this user has no cards yet.
Peg Kaplan's bidding problem: A QTxx AKQxxx Ax
I think you might be right. I am curious what the 7NTers are planning to bid? Just 2 or something else?
Robert Schachter's bidding problem: JT9 T7 QT43 J752
I think with 21-22 and a moderate five card suit partner might double and bid his suit. With an Acol strong two he would jump to three spades.
Robert Schachter's bidding problem: JT9 T7 QT43 J752
I think it would be near forcing since 2S has a minimum of 16 and I have denied a positive. Does that seem logical to you?
Robert Schachter's bidding problem: JT9 T7 QT43 J752
2 woulld be everything from a minimum 1 opener to a near game force. 3! and a cue bid would be stronger.
Robert Schachter's bidding problem: JT9 T7 QT43 J752
I didn’t ask. But I assume given the vulnerability that he would probably have six or more diamonds.
Robert Schachter's bidding problem: J96543 --- 65 AT964
What happened was that LHO, who had a seventeen count pulled the wrong card from the bidding box.
Guidelines for judgment decisions?
If the east and west hands were reversed would you make the same ruling?
Robert Schachter's bidding problem: KQJ432 AK64 4 85
That makes sense . Thanks.
Should this slam be made ?
Phillip Martin had an article pertaining to this kind of problem called “Majority rule” if I remember it took a large differential to hook the jack in this kind of situation (I think it was six or more).
Robert Schachter's bidding problem: KQJ432 AK64 4 85
Just curious, but are the 2 bidders intending to bid 3NT over 3? Also i assume part of the gain from the cue bid is partner might call 3, right?
.

Bottom Home Top