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Bridge Winners Profile for Robert Schachter

Robert Schachter
Robert Schachter
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Member Since
Feb. 26, 2014
Last Seen
3 hours ago
Member Type
Bridge Player

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Robert Schachter's bidding problem: AJ3 74 AQ9743 A9
Does 3 just show a desire to force and no clear bid or does it sometimes show heart support?
Robert Schachter's bidding problem: J75 K2 KQJT3 Q65
Also, you probably have a trump trick.
ATB - Hopeless grand
Couldn’t 4S be KQx, Qxxx,JT,AKxx ? How would you distinguish between the two hands without some sort of relay structure?
ATB - Hopeless grand
Does the squeeze work if south has four clubs and the KQ? Never mind I see it now.
ATB - Hopeless grand
How would you get to seven using Rich’s example reducing the hand by one club?
Andy Caranicas's bidding problem: AQ98 J QT96543 2
You can survive many 4-1 splits when the shortness is in front of declarer. Same with a 3-0 split except in reverse. Isn’t that right? Also adding the jack or ten of trumps will improve prospects. Though a trump lead will leave you an entry short if diamonds split ...
Andy Caranicas's bidding problem: AQ98 J QT96543 2
Kx of diamonds risks a diamond ruff too.
Andy Caranicas's bidding problem: AQ98 J QT96543 2
I think there is some truth to that. However a singleton can also be useful. Kxxxxx,!Axx,x,Axx yields a slam. If you bid diamonds partner will think a singleton diamond is a negative. Also partner’s Ax still leaves a loser in that suit. .
Andy Caranicas's bidding problem: AQ98 J QT96543 2
Because partner needs to hold an extra useful card when your suit is not headed by the ace or king.
Andy Caranicas's bidding problem: AQ98 J QT96543 2
I think 2 would work better if diamonds were headed by the king or ace.
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