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Bridge Winners Profile for Stéphane Turcotte

Stéphane Turcotte
Stéphane Turcotte
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Basic Information

Member Since
Dec. 6, 2013
Last Seen
Dec. 10
Member Type
bridge player

Bridge Information

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Benoit Lessard's bidding problem: Axxx xx K9x AQ9x
Very good hand for an already showed 12-14 count. Ctrl riched, easy 3
3rd bid by opener
I like 3 with the proposed hand. In the case where partner has 54 in the majors, it is likely that you will want to be in a 7 cd spade fit if partner cant cover the diamonds. 3 also allows opener to bid his 5th heart and ...
3rd bid by opener
That is possible as well. Thats why im looking for opinions.
3rd bid by opener
So with 5242, you would bid 2N only if you have Hx in both suits, otherwise, you bid 3 or 3?
Benoit Lessard's bidding problem: AK8xx xx K9xx K5
I think both 3 and 3 are OK, but requires agreement after a minor fit is agreed, since we first try to find 3N.
Benoit Lessard's bidding problem: AK8xx xx K9xx K5
If partner cant find 3NT bid and bids 4S with 2 little and a heart stopper well just too bad. I bid 3
Stéphane Turcotte's bidding problem: Axx AKJx AJx AKJ
Below the 9
Stéphane Turcotte's bidding problem: Axx AKJx AJx AKJ
The full romex stayman that I play is: 3 = May have 5 --3 =Asks about and promiss at least 3 ----3 = Exactly 3 ----3N = Exactly 2 ----4x = Exactly 5, ctrl in that suit --3N = To play --4m = Natural 3 = Exactly ...
Stéphane Turcotte's bidding problem: Axx AKJx AJx AKJ
There is one bid here that I did not consider which I like a lot: 5 That would be like a sort of last train asking for extra cards... Here it's clear I would be asking for side queens.
Stéphane Turcotte's bidding problem: Axx AKJx AJx AKJ
Singleton would have been worth a 4D call. I have inference of not singleton in the minors
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