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Bridge Winners Profile for Steve Myerson

Steve Myerson
Steve Myerson
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Basic Information

Member Since
April 13, 2013
Last Seen
March 15
Member Type
Bridge Player
United States of America

Bridge Information

ACBL Ranking
Bronze Life Master
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Oren Kriegel's bidding problem: 2 J8752 AJT2 J75
What's partner's rebid with 4=3=2=4? Raise hearts or bid spades?
Walter Schmid's bidding problem: 943 Q KJT32 Q843
I have 6 more points than I've already shown. If partner thinks I can make 5 opposite a yarborough, 6 should have some play.
David Stevenson's bidding problem: AK6 A AK52 AQ983
4N, with the expectation that partner will take it as RKC. After the none reply, I will ask for the queen and any kings. I'm bidding 6 at a minimum (SDAM). This way I can bid a confident 7 if partner shows the diamond queen and club ...
Chris Derrick's bidding problem: AKQT83 A --- JT7654
What is your action if the next 2 opinions are pass? Do I presume leading the ace of spades?
Winston Chang's bidding problem: K Q9532 AQ98 652
Given that I opened this piece of Swiss cheese and partner didn't act over 2, it wouldn't surprise me to see NS making 4.
Benoit Lessard's bidding problem: KQ9x AQ A7xxx AK
There are 2 passes before you bid, including partner's "forced" 10 second delay. Surely that's enough time to contemplate your call before it's your turn.
How greedy are you?
I just relayed the conversation at the table. Declarer asked me if I would have finessed. I said that she had a tough choice. Either the ace or queen could be correct. West volunteered the comment about leading a diamond from the jack rather than a club from AQ. Entire ...
How greedy are you?
[b]if West has the AQ of clubs without the diamond king he probably would play his second highest diamond on opening lead to encourage partner to switch to clubs if he wins the diamond[/b] This was in fact the holding in the West hand, but I don't ...
Nathan Finkle's bidding problem: 87 AQJ75 975 Q83
If that's a possibility opposite an unpassed partner, then I would be leery of doubling also.
Nathan Finkle's bidding problem: 87 AQJ75 975 Q83
There is that risk, but even though declarer knows the hearts are 5-0, I'm still getting 2 heart tricks. So I'm counting on 2 tricks from partner. Is that unrealistic?
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