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Bridge Winners Profile for Troels Bjerre

Troels Bjerre
Troels Bjerre
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Basic Information

Member Since
March 21, 2013
Last Seen
9 hours ago
Member Type
Bridge Player
Country
Spain

Bridge Information

ACBL Ranking
None
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Sasha Cooper's bidding problem: T987 A3 A95 AKQ5
Worth 18 hp.
Ed Judy's bidding problem: AJ6 K 654 AKQJT5
3S is not so bad - 1S is most likely 5 cards.
Thomas van der Hoeden's bidding problem: 4 AQ42 KQT7 9854
A 5-4 fit and at least 22 hcp. Sounds like 4H. I am being polite.
William Kochneff's bidding problem: 42 7 AT9873 AKJ5
Well, a good partner will respect your judgement and not bid 3NT over 3C. The experts can get to 5C, the rest of us follow Hamman`s advice and bid 3NT.
William Kochneff's bidding problem: 42 7 AT9873 AKJ5
But 3C can be passed - shows unwillingness to play in no trumps. Bidding 3C reminds me of Frank Vine: "How I challenged the champs and made them cry."
William Kochneff's bidding problem: 42 7 AT9873 AKJ5
Partner passed - so 3NT.
Jenish Shah's bidding problem: QT87 972 A2 KT83
Then the bid is 2NT - according to Robson & Segal.
David Coles's bidding problem: K987643 --- K9 K762
Rather than counting points i play 2S as 6 losers. This hand qualifies. The suit is a minor flaw, but then: only 5 losers.
Rich Newell's bidding problem: QT53 AK AT KQJ53
Now 2S. But the hand seems closer to 20 than 19.
Mark Bartusek's lead problem: 842 J2 QT73 T542
First ask about Walsh - this sequence is a classic trap. Yes, with a hand strong enough for game you should not bypass diamonds - but does South think that?
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