Join Bridge Winners

Bridge Winners Profile for Kurt Häggblom

Kurt Häggblom
Kurt Häggblom
  • 0
  • 5
  • 0
  • 0

Basic Information

Member Since
Aug. 18, 2012
Last Seen
15 hours ago
Member Type
Bridge Player

Bridge Information

ACBL Ranking
Sorry, this user has no cards yet.
Another Question for Mathematicians--well...Statisticians
I can repeat my calculations for 26 cards (2 hands) instead of 13 cards (1 hand). This gives Var(X) = 16/17 and Cov(X,Y) = -4/51, which for both is an increase by the factor 4/3. Thus, the result sqrt(1160/51) is obtained. Does Helene have ...
Another Question for Mathematicians--well...Statisticians
The honor card distribution is a multivariate hypergeometric distribution. The following expressions follow from formulas for that distribution (see, e.g., Wikipedia). The variance of the number of honor cards of a given rank X (J, Q, K or A) is Var(X) = 12/17. There is a negative correlation ...
Question for Mathematicians
Good guess.
Question for Mathematicians
To obtain my results, I have used Frederick Frost's "bridge odds complete" from 1971. It is known to contain some errors, but hopefully not in the figures I have used. The result depends on what honor cards your 7 HCP contains. AK gives a different result than QQQJ. For ... is time to consider an electronic Bridge Bulletin & Daily Bulletin?
ACBL already applies this to "foreign" addresses. If you want the printed issue, you have to pay extra. I don't, so I only have access to the on-line version. Addition. "I don't" refers to "pay extra", I would like to have the printed version.
Google Knows Bridge
Around 1975 I wanted to generate deals for bidding practice during the forthcoming summer. I had access to a Honeywell H-316 computer with 16K of memory which could be programmed in FORTRAN using punched tape. The problem was that I didn't have a random number generator, but then I ...
Zia would know what to do
Yes, that's the main advantage of trying the drop when spades are 4-4. When they are 5-3, the entry is not needed for a heart finesse.
Zia would know what to do
That I did above: "I think we can assume leader to have one of the distributions 4=4=4=1, 4=4=3=2, 4=4=2=3, 4=3=4=2, 4=3=3=3, 4=2=4=3. A priori, they occur in the ratios 15 : 30 : 18 ...
More ACBL Stuff
Yes, that adds C(5,1)xC13,7) hands for the finesse, which changes the ratio to 8:5 in favor of the drop. Playing A, four clubs, then spades also preserves some minor squeeze possibilities. Edit: Jxx also has to be added, which makes the ratio 8:9 in ...
More ACBL Stuff
After the hearts, I think there are about C(6,3)xC(13,6) hands with spades 3-3 and about C(5,3)xC(13,5) hands with East having Jxxx. That's a ratio 8:3 in favor of the drop.
Not following anyone yet

Bottom Home Top