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Bridge Winners Profile for Leonard Helfgott

Leonard Helfgott
Leonard Helfgott
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Basic Information

Member Since
Aug. 20, 2015
Last Seen
7 hours ago
Member Type
Bridge Player
Country
United States of America

Bridge Information

Favorite Bridge Memory
Winning a 1981 Sectional against strong LMs for Intermediate Player of the Year---back in the day!
Regular Bridge Partners
Burrell Humphreys, Irwin Miller, Sue Fulton, Alex Salpeter, Ed Landau, Peter Stein,
ACBL Ranking
Sapphire Life Master
Sorry, this user has no cards yet.
Fred King's bidding problem: 9 9642 QJT KQJT5
If you have an understanding that as a passed hand you likely have a second place to play (likely hearts for lack of a 2NT call) then 3C is much safer.
Another "what is standard?" poll
What about 3C with say xx KQTx xx KTxxx?
RHO open 1NT, you have 2524 and 15 points
I prefer Mod Capp. Or ASTRO so will bid 2C to show M&m in ModCap or H&m in ASTRO. Would not pass. If playing one of the above conventions, would bid not pass.
Another "what is standard?" poll
I think it should be a 1-round force, but more importantly as Michael Rosenberg suggested, partner’s should agree on F vs. NF and what Hand types are appropriate. I do think doubler should almost always have exactly 3H. Advancer might have a good 4H&5C 8 count for example ...
Another "what is standard?" poll
Just playing Devils Advocate to those above, perhaps Doubler has a single stopper plus majors, 15 hcp and preferred Double to 1NT overcall with AQJx KJx Axx xxx. I don’t think 1NT is ‘automatic” vs. a Double or even a 1S overcall. After Double and partner’s 2H jump ...
Another "what is standard?" poll
14 might be a tad light but I’m with Phil on this.
Another "what is standard?" poll
Yes. The 2H jump already implies Inv values, say 8-11, so the 2NT is likely 3H and offering a choice of games lIke 3NT or 4H or even spades opposite a 4-5 10 count. I would think 15-16 is sufficient.
Leonard Helfgott's bidding problem: K52 QT4 J96 QT87
Just to touch off the subject, if we assume a priori that AQJxx xxx Kx KJx and the actual AQJxx xxxx K KJx both have 7 losers, the 2D bid on left increases the Loser Count of the balanced hand by 1 (assuming DK is now worthless in both cases ...
Marginal New Minor Forcing Hand
Craig: I love these computer simulations/analyses! Keep ‘em coming. BTW how does 1NT ever tie 2S at BAM? Doesn’t 120 beat 110 at BAM? Maybe -50 ties -50? At IMPs where the plus is key, I would expect 2S to win except for 5332 oppos. A doubleton.
For those of a certain age
Well, when I started college (1965) I had a broken leg, on crutches, and had to climb stairs to ride the NYC subway/el system. One time I got on the subway car, on crutches with bookbag and the car was completely filled, no seats. How many of the 60 ...
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