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Bridge Winners Profile for Martin Lindfors

Martin Lindfors
Martin Lindfors
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Member Since
Sept. 24, 2017
Last Seen
2 hours ago
Member Type
bridge player

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Martin Lindfors's bidding problem: J42 A AKT AKJT32
Partner had a functional zero-count with a spade singleton and club length. I bid the making 5 game, while the opponents have 5 spade tricks off the top in NT. On a heart lead 3NT obviously makes though.
Hand from Gatlinberg KO’s
That is a reasonable approach, but I would swap 3 and 2NT so that 3 = 44 in majors. That should save space in this case, while the additional space consumed when opener is (44)(32) is a small concern.
Leo Lasota's bidding problem: T764 732 J87 A42
Negative double for majors.
Martin Lindfors's bidding problem: 3 J9873 KQJ876 T
That depends on what you consider a game forcing hand. In this case (as will be revealed soon), they are certainly being optimistic.
Martin Lindfors's bidding problem: 3 J9873 KQJ876 T
We are playing against a pair which likes opening strong 2 on essentially any hand with 9 playing tricks. I will post the full bidding and the outcome of the board in a day or two.
Rohit Gupta's bidding problem: --- K742 AQJ986 KJ3
Why is partner cueing a second control in clubs? Is it just affirming that his control is the ace? Does not make sense.
Thibault Wolf's bidding problem: 53 QT92 AKQJ6 42
Would bid Stenberg/Jacoby 2NT with this hand the first time.
Runout (Wriggle) Sequences for Penalty Double of 1NT
Strong notrump partnerships often don't play any of those escape sequences. Weak notrump partnerships probably do.
Martin Lindfors's bidding problem: K53 Q 92 KQJ7653
Well, for this hand, partner was sitting on a monster. After my 2 rebid, he keycards and puts us in 6NT. However, if I had opened 3, he can find the cold 7NT, since he knows the clubs run, and can find the K from a specific ...
Shawn Drenning's bidding problem: AT94 --- A KQ765432
4 with better club pips. The 7 is a likely loser, a 10 might not be.
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